Poison

34. Find First and Last Position of Element in Sorted Array

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class Solution {
public int[] searchRange(int[] nums, int target) {
int startIndex = findStartIndex(nums, target);
if (startIndex == -1) {
return new int[]{-1, -1};
} else {
return new int[]{startIndex, findEndIndex(nums, target)};
}
}

private int findEndIndex(int[] nums, int target) {
int left = 0, right = nums.length - 1; // [left, right]
while (left <= right) {
int mid = (left + right) >>> 1;
if (nums[mid] < target) {
left = mid + 1;
} else if (nums[mid] > target) {
right = mid - 1;
} else {
left = mid + 1;
}
}

// now: right, left
if (right == -1 || nums[right] != target) {
return -1;
}

return right;
}

private int findStartIndex(int[] nums, int target) {
int left = 0, right = nums.length - 1; // [left, right]
while (left <= right) {
int mid = (left + right) >>> 1;
if (nums[mid] < target) {
left = mid + 1;
} else if (nums[mid] > target) {
right = mid - 1;
} else {
right = mid - 1;
}
}

// now: right, left
if (left == nums.length || nums[left] != target) {
return -1;
}

return left;
}
}

注意此题是搜索第一个和最后一个位置而不是搜索插入位置,所以需要比较最后停留的位置的值是否为目标值。

Reference

34. Find First and Last Position of Element in Sorted Array