645. Set Mismatch 发表于 2022-01-25 123456789101112131415161718192021222324class Solution { public int[] findErrorNums(int[] nums) { int[] res = new int[2]; for (int i = 0; i < nums.length; i++) { int num = Math.abs(nums[i]); if (nums[num - 1] > 0) { nums[num - 1] *= -1; } else { // 如果已经小于 0 了,说明数字重复,注意此处应该取 num res[0] = num; } } for (int i = 0; i < nums.length; i++) { if (nums[i] > 0) { // 如果没有被翻转,说明该索引本该存储的数字丢失 res[1] = i + 1; } } return res; }} 1234567891011121314151617181920212223class Solution { public int[] findErrorNums(int[] nums) { for (int i = 0; i < nums.length; i++) { while (nums[i] != nums[nums[i] - 1]) { swap(nums, i, nums[i] - 1); } } for (int i = 0; i < nums.length; i++) { if (nums[i] != i + 1) { return new int[]{nums[i], i + 1}; // 注意按题目顺序返回 } } return new int[0]; } private void swap(int[] nums, int i, int j) { int tmp = nums[i]; nums[i] = nums[j]; nums[j] = tmp; }} Reference645. Set Mismatch