Poison

460. LFU Cache

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
class LFUCache {

private final Map<Integer, Integer> map;
private final Map<Integer, Integer> keyToFreqMap;
private final Map<Integer, Set<Integer>> freqToKeySetMap;
private final int capacity;
private int minFreq;

public LFUCache(int capacity) {
this.map = new HashMap<>();
this.keyToFreqMap = new HashMap<>();
this.freqToKeySetMap = new HashMap<>();
this.capacity = capacity;
this.minFreq = 1;
}

public int get(int key) {
Integer value = map.get(key);
if (value == null) {
return -1;
} else {
increaseFreq(key);
return value;
}
}

private void increaseFreq(int key) {
int previousFreq = keyToFreqMap.remove(key);
keyToFreqMap.put(key, previousFreq + 1);

Set<Integer> keySet = freqToKeySetMap.get(previousFreq);
keySet.remove(key);
freqToKeySetMap.computeIfAbsent(previousFreq + 1, k -> new LinkedHashSet<>()).add(key);

// 注意此处更新 minFreq 的条件,如果之前当前 key 是最低频率,且频率增加后最低频率无元素才更新 minFreq
if (previousFreq == minFreq && keySet.isEmpty()) {
minFreq += 1;
}
}

public void put(int key, int value) {
if (capacity == 0) {
return;
}

Integer previousValue = map.put(key, value);
if (previousValue == null) {
// 注意此处,如果是先 put 再淘汰,则需要 map 中元素个数超过 capacity 再淘汰
if (map.size() > capacity) {
// 淘汰一个最低频的
Set<Integer> keySet = freqToKeySetMap.get(minFreq);
int evictedKey = keySet.iterator().next();

map.remove(evictedKey);
keyToFreqMap.remove(evictedKey);
keySet.remove(evictedKey);
}

keyToFreqMap.put(key, 1);
freqToKeySetMap.computeIfAbsent(1, k -> new LinkedHashSet<>()).add(key);
minFreq = 1;
} else {
increaseFreq(key);
}
}

}
Reference

460. LFU Cache