剑指 Offer 22. 链表中倒数第k个节点 发表于 2022-04-26 12345678910111213141516class Solution { public ListNode getKthFromEnd(ListNode head, int k) { ListNode first = head; for (int i = 0; i < k; i++) { first = first.next; } ListNode second = head; while (first != null) { first = first.next; second = second.next; } return second; }} Reference剑指 Offer 22. 链表中倒数第k个节点