Poison

198. House Robber

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class Solution {
    public int rob(int[] nums) {
        int n = nums.length;

        if (n == 1) {
            return nums[0];
        }

        // 定义 dp[i] 为截止 i 号房屋时能偷窃到的最高金额
        int[] dp = new int[n];
        dp[0] = nums[0];
        dp[1] = Math.max(nums[0], nums[1]);

        for (int i = 2; i < n; i++) {
            dp[i] = Math.max(dp[i - 2] + nums[i], dp[i - 1]);
        }

        return dp[n - 1];
    }
}
Reference

198. House Robber
剑指 Offer II 089. 房屋偷盗