56. Merge Intervals 发表于 2022-10-04 12345678910111213141516171819class Solution { public int[][] merge(int[][] intervals) { // 只需按 start 排序 Arrays.sort(intervals, Comparator.comparingInt(o -> o[0])); List<int[]> intervalList = new ArrayList<>(); intervalList.add(Arrays.copyOf(intervals[0], 2)); for (int i = 1; i < intervals.length; i++) { int[] pervInterval = intervalList.get(intervalList.size() - 1); if (intervals[i][0] <= pervInterval[1]) { pervInterval[1] = Math.max(pervInterval[1], intervals[i][1]); } else { intervalList.add(Arrays.copyOf(intervals[i], 2)); } } return intervalList.toArray(new int[0][]); }} Reference56. Merge Intervals